4^1-7x=5^x

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Solution for 4^1-7x=5^x equation: 



4^1-7x=5^x

We move all terms to the left:

4^1-7x-(5^x)=0

We add all the numbers together, and all the variables

-7x-5^x+4=0

We move all terms containing x to the left, all other terms to the right

-7x-5^x=-4

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